26.27 取Unicode字符串的长整型值(little-endian序)

Q:

下面这段Python3代码显示Unicode字符串"www.baidu.com"前16字节的长整数形式，2
个长整数，little-endian序:

--------------------------------------------------------------------------
x   = 'www.baidu.com'
x   = "".join([c+'\0' for c in x]).encode( 'latin-1' ).hex()
y   = x[:16]
''.join(map(str.__add__, y[-2::-2], y[-1::-2]))
y   = x[16:32]
''.join(map(str.__add__, y[-2::-2], y[-1::-2]))
--------------------------------------------------------------------------

'002e007700770077'
'0064006900610062'

我只会这么矬的办法，不知更好的办法是啥？

A: bluerust 2020-03-07

Python3

--------------------------------------------------------------------------
import struct

x   = "www.baidu.com"
x   = bytes( x, encoding='utf-16' )[2:]
[hex(struct.unpack( "<Q", x[i:i+8] )[0]) for i in range(0 ,len(x)//8*8, 8)]
--------------------------------------------------------------------------

['0x2e007700770077', '0x64006900610062', '0x6f0063002e0075']

--------------------------------------------------------------------------
import hexdump

x   = "www.baidu.com"
x   = bytes( x, encoding='utf-16' )[2:]
['0x' + ''.join(map(str.__add__, y[-2::-2], y[-1::-2])) for y in hexdump.dump( x, size=16, sep=',' ).split( ',' )]
--------------------------------------------------------------------------
import hexdump

x   = "www.baidu.com"
x   = bytes( x, encoding='utf-16' )[2:]
['0x' + ''.join(map(str.__add__, y[-2::-2], y[-1::-2])) for y in hexdump.dump( x, size=16 ).split()]
--------------------------------------------------------------------------

['0x002E007700770077', '0x0064006900610062', '0x006F0063002E0075', '0x006D']